In this post, a clear explanation on KVL and KCL has been provided. Kirchoff’s Current Law and Kirchoff’s Voltage Law can be applied only a closed path or loop.
Kvl & Kcl
Also, read: Equivalent Resistance | Calculation
In the above circuit, the I1, I2, I3, I4, and I5 are the currents flowing through each terminal. The Current I1 and I2 flowing towards the junction and the currents I3, I4, and I5 flowing away from the circuit.
The KCL equation can be written as
I1 + I2 + (-I3) + (-I4) + (-I5) = 0
I1 + I2 = I3 + I4 + I5
Also, Read: Bcd -> Excess-3 Converter
Kirchoff’s Voltage Law:
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While applying KVL, the clockwise direction is taken as a positive and the anti-clockwise direction is taken as a negative.
Here we have three sources, so in order to include all sources into the theorem, we need to apply KVL for the loops ABCDEFA and ABEFA.
For Loop ABCDEFA,
I1R1 + I1R2 + I3R4 + I3R5 + I4R6 + I1r1 + I3r3 = E1 + E3
For Loop ABEFA,
I1R1 + I1R2 + I2R3 + I4R6 + I2r2 + I1r1 = E1- E2
Also, Read: Excess-3 Converter -> bcd converter
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