Connect with us

Hi, what are you looking for?

# How to calculate Equivalent Resistance?

Equivalent Resistance of a circuit is obtained by calculating parallel and series elements in a circuit. A circuit may contain many series and parallel connected elements. In this topic on How to calculate Equivalent Resistance, we have to simplify the circuit elements.

To find the value of a resistor, a multimeter of Resistor Color Coding method can be used.

To calculate the Equivalent Resistance of the above circuit we need to simplify each part. In this example, start simplifying from the parallel resistor configuration.

The formula to use:

Rp = R1R2/ (R1 + R2)

Rs = R1 + R2

Let’s start to simplify from each part.

Code Conversion | Excess-3 T0 Bcd Converter

In this part, the following resistors 6Ω are 7Ω connected in a parallel configuration.

Rp = 6 * 7/ (6 + 7)

Rp = 42/ 13

Rp = 3.2307

Rp = 3.231Ω

(Good practice is to round off three digits)

Here the resistors 2Ω and 4Ω are connected in a parallel configuration.

Rp = 2 * 4/ (2 + 4)

Rp = 8 / 6

Rp = 1.3333

Rp = 1.333Ω

Methods of Neutral Grounding | Neutral Earthing

Here the resistors 3Ω and 5Ω are connected in a parallel configuration.

Rp = 3 * 5 /(3 + 5)

Rp = 15 / 8

Rp = 1.875 Ω

Here the 8Ω and 9Ω are connected in a parallel configuration.

Rp = 8 * 9 / (8 + 9)

Rp = 72/ 17

Rp = 4.235 Ω

Power System Protection | Relay Roles

Here the following resistors 1Ω and 10Ω are connected in a parallel configuration.

Rp = 1 * 10/ (1 + 10)

Rp = 10/ 11

Rp = 0.909 Ω

Now add all the values which you got from simplifying the Parallel Configuration. The reason why we are adding is each and everything is connected in a series configuration.

Now the circuit is simplified as follows.

Rs = 3.231Ω +  1.333Ω + 1.875 Ω +  4.235 Ω + 0.909 Ω

Rs = 11.583 Ω  which is also the.

Rab = 11.583 Ω

This example is applicable only for simple circuits. For circuits with more complexity, there were network reduction theorems. We can’t solve complex circuits only with this formula, This doesn’t mean we can’t solve but what I am saying is it was practically difficult to solve.

Here I have shown an example with 2 parallel resistors. For ‘n’ parallel resistors use this formula to reduce the network.

1/Rp = (1/R1) +(1/R2) + (1/R3)….. + (1/Rn)

or

Rp = R1R2R3Rn/ (R1 + R2 + R3 + Rn)

## You may also interested in:

### Digital Logic Circuits

Excess-3 to BCD converter In this post on code conversions, we are going to see Excess-3 to BCD converter using k map technique.  K-map If you...

### Digital Logic Circuits

BCD to Excess-3 converter In this post on a code converter, we are going to see BCD to Excess-3 converter using the k-mapping technique....

### Basics

The Scientific Calculator is an advanced version of an ordinary calculator which helps us to solve complex arithmetic problems. The Normal Calculator consists of...

### Law

For those of you who are waiting for their personal injury claim to be processed, your case might be rejected if it already has...

### Sports

Gambling is a type of activity that can attract almost all the people towards itself and behind this strong attracting power of gambling stays...

Many companies today create strategic business growth plans. However, the process doesn’t bear any fruits. This means the company wasted time and resources to...

### Health Care

It’s an incredible feeling when you make the choice to go vegan! You realize how much willpower you truly have, and your body immediately...

### CBD

With the rise of the kingdom of premium e-juice flavours, the elderly throne of cheap vape juices has been overshadowed by it. The most...

### Sports

Mistakes should cheap money-back guarantee is extremely true in online casino gambling. However, there are just some players or gamblers of which are rich...